Remove `Color.contrasted()` as its behavior is barely useful

Returning the most contrasting color isn't a trivial task, as there
are often many possible choices. It's usually best left for the user
to implement using a script.

1 files changed, 0 insertions, 12 deletions

diff --git a/core/color.cpp b/core/color.cpp
index c61ee0e64a..4047ca5037 100644
--- a/core/color.cpp
+++ b/core/color.cpp
@@ -217,12 +217,6 @@ void Color::invert() {
 	b = 1.0 - b;
 }
 
-void Color::contrast() {
-	r = Math::fmod(r + 0.5, 1.0);
-	g = Math::fmod(g + 0.5, 1.0);
-	b = Math::fmod(b + 0.5, 1.0);
-}
-
 Color Color::hex(uint32_t p_hex) {
 	float a = (p_hex & 0xFF) / 255.0;
 	p_hex >>= 8;
@@ -284,12 +278,6 @@ Color Color::inverted() const {
 	return c;
 }
 
-Color Color::contrasted() const {
-	Color c = *this;
-	c.contrast();
-	return c;
-}
-
 Color Color::html(const String &p_rgba) {
 	String color = p_rgba;
 	if (color.length() == 0) {